05/10/30 tough puzzle from sudoku.com.au

Want to see the whole thing? A complete proof
Just stuck somewhere and willing to have still work to do ? Short hints for a proof
Studied enough forbidding chains to appreciate this Forbidding-chain-like proof
Understood the equivalent puzzles stuff? Equivalence with 09/24

A complete proof

1) First eliminations lead to 23 filled cells. (if needed : h3=3%col, i5=3%col, b7=3%col)

2) Look at only possibles h9=4,h8=4 in their col. They forbid{`i9=4`, `g9=4`, `i7=4`, `g7=4`}.
Look at only possibles b1=9,b2=9 in their col. They forbid{`a3=9`, `c3=9`, `c1=9`, `a1=9`}.
Now simple eliminations take place again, leading to 46 filled cells. (if needed : d3=9%row, a7=9%row, e9=9%row, f7=4%row, i3=4%row, e1=4%row, e6=3%col, d6=6%row, g6=8%row, i7=6%row, h4=6%row, h2=9%col, b1=9%row, g5=4%col, c5=9%row, g4=9%row, i4=1%block, g7=5%block, g9=1%block, i2=5%row, d7=1%row, i1=8%block, i9=7%col)

3) Look at only possibles b2=2,b2=7 in their cell. Whether b2=2 (in which case g2=7%cell) or b2=7, in both cases, we have no more {`d2=7`, `f2=7`, `e2=7`}.
Look at only possibles b2=7,b2=2 in their cell. Whether b2=7 (in which case g2=2%cell) or b2=2, in both cases, we have no more {`f2=2`, `e2=2`, `d2=2`}.
Then simple eliminations take place again, up to 51 filled cells. (if needed : d2=8%cell, f5=8%row, e5=1%block, f2=1%block, e2=6%row)

4) Look at only possibles d8=7,d1=7 in their col. Whether d8=7 (in which case e8=2%cell) or d1=7 (in which case f3=2%cell), in both cases, we have no more {`f9=2`, `f8=2`}.
Look at only possibles d8=7,d1=7 in their col. Whether d8=7 (in which case e8=2%cell) or d1=7 (in which case d9=3%col), in both cases, we have no more {`d9=2`}. Now easy to 54 filled cells. (if needed : d9=3%cell, f1=3%row, f9=6%cell)

5) Look at only possibles e8=2,d8=2 in their block. They forbid{`c8=2`, `a8=2`, `b8=2`}.
From here, simple eliminations lead to unique solution. (if needed : b2=2%col, g1=2%block, f3=2%block, a3=7%row, c3=8%row, b6=7%row, g2=7%row, d1=7%row, c6=4%row, a6=1%block, c8=1%block, a8=6%row, h8=8%row, a9=8%row, c9=2%block, a5=2%block, e4=2%block, d8=2%block, f4=7%row, e8=7%row, c1=6%row, f8=5%row, d5=5%row, c4=5%row, a1=5%row, h9=4%row, b8=4%row)

Short hints for a proof

The hard step is at 51 filled :


1) First eliminations to 23 filled cells.
2) Look at only possibles 4 in their column Ch. Look at only possibles 9 in their column Cb. Remove some possibles. Now easy eliminations take place again, leading to 46 filled cells.
3) Look at only possibles 27 in b2g2. Remove some possibles. Then simple eliminations take place again, up to 51 filled cells.
4) Looking at only possibles 7 in their column Cd, remove possibles {d9=5,f9=5, f8=5} (beware, heptagons).
5) Look then at only possibles 2 in their block Be8. Remove some possibles. From here, simple eliminations lead to unique solution.

Forbidden-chain-like proof

The hard step is at 51 filled :


1) easy to 23 filled.
2) (h9=4)==(h8=4) forbids {i9=4, g7=4, g9=4, i7=4} ; (b1=9)==(b2=9) forbids {a1=9, c1=9, a3=9, c3=9}. Now easy to 46 filled.
3) (g2=7)==(g2=2)--(b2=2)==(b2=7) forbids {e2=7, f2=7, d2=7} ; (g2=2)==(g2=7)--(b2=7)==(b2=2) forbids {d2=2, e2=2, f2=2}. Now easy to 51 filled.
4) (e8=2)==(e8=7)--(d8=7)==(d1=7)--(d1=3)==(d9=3) forbids {d9=2} ; (e8=2)==(e8=7)--(d8=7)==(d1=7)--(f3=7)==(f3=2) forbids {f9=2, f8=2}. Now easy to 54 filled.
5) (e8=2)==(d8=2) forbids {c8=2, b8=2, a8=2}. Now easy to unique solution.

Equivalence with 09/24

Now applying the same "dictionary" (changing rows, columns, values) to proof of 05/09/24 you will mechanically get a proof of today's. E.g. first filled cell in 05/09/24 was g5=1%block; in today's it becomes i5=3%block. Try it ! Or see the method explained step by step on 10/08 example.
In case that you be lazy enough not to find it by yourself, see above hints for today's proof (automatically derived from 05/09/24's proof).

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